##### Poissons Ratio
$\nu = - \dfrac{\mathrm{lateral\ strain}}{\mathrm{longitudinal\ strain}}$

• Describe and define Poisson’s ratio.

###### Solved Example: 41-3-01 Page 131

The value of Poisson’s ratio for steel is between:

###### Solved Example: 41-3-02 Page 131

Poisson’s ratio is defined as the ratio of:

###### Solved Example: 41-3-03 Page 131

A bar of 30 mm diameter is subjected to a pull of 60 kN. The measured extension on gauge length of 200 mm is 0.1 mm and change in diameter is 0.004 mm. Calculate Poisson’s ratio.

###### Solved Example: 41-3-04 Page 131

Poisson's ratio of a material is 0.5. Percentage change in its length is 0.04%. What is the change in percentage of diameter?

###### Solved Example: 41-3-05 Page 131

Which of the following statements is NOT true?

###### Solved Example: 41-3-06 Page 131

Which of the following describes the concept of Poisson's ratio most accurately?

###### Solved Example: 41-3-07 Page 131

What is the unit of the modulus of elasticity?

###### Solved Example: 41-3-08 Page 131

Within elastic limit, the volumetric strain is proportional to the hydrostatic stress. What is the constant that relates these two quantities called?

###### Solved Example: 41-3-09 Page 131

What is another term for modulus of rigidity?

###### Solved Example: 41-3-10 Page 131

The ratio of lateral strain to the linear strain within elastic limit is known as:

###### Solved Example: 41-3-11 Page 131

Young’s modulus is defined as the ratio of:

###### Solved Example: 41-3-12 Page 131

The materials having same elastic properties in all directions are called:

###### Solved Example: 41-3-13 Page 131

The value of modulus of elasticity for mild steel is of the order of:

###### Solved Example: 41-3-14 Page 131

A metallic rod of 500 mm length and 50 mm diameter, when subjected to a tensile force of 100 kN at the ends, experiences, an increase in its length by 0.5 mm and a reduction in its diameter by 0.015 mm. The Poisson's ratio?

Solution:

Lateral strain $=\dfrac {0.015}{50}=0.003$

Longitudinal strain $=\dfrac {0.5}{500}=0.001$

Poisson's ratio $\nu =\dfrac {0.0003}{0.001}=0.3$