### Isochoric Process- Constant Volume

• Calculate total work done in a Constant Volume thermodynamic process.

A constant volume process is the vertical path dV = 0 in the P-V plane - up if heat is added and down if heat is removed. Because dV = 0, the work done is $dW = - P dV = 0$ The First Law of Thermodynamics then states: $dU= dQ + dW = dQ + 0 = dQ$ $dQ = dU = mC_V(T_2 - T_1)$

### Solved Example:

#### 72-2-01

Isochoric process is one in which:

Solution:
In isochoric process, volume remains constant. Hence, there is no mechanical work done by the system.