Algebra and Trigonometry
Algebraic Equations and Roots
Learning Objectives:
- Recognize the relationship between the roots of a quadratic equation and its coefficients
- Identify the sum and product of the roots.
- Form a quadratic equation given its roots, including when the roots are integers, rational numbers, real numbers, and complex numbers, and solve related problems.
Quadratic Equation:
Any equation in the form of \(ax^2 + bx + c = 0\) where a \(\neq\) 0 is referred as quadratic eqation and its roots are given by the formula: \[x_{1,2} = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
The \(b^2-4ac\) part of this equation is called the discriminant. Based on its value, there are three possibilities:
If \(b^2-4ac\) > 0 then the roots are real and distinct.
If \(b^2-4ac\) = 0, then the roots are same (repeated) but real.
If \(b^2-4ac\)< 0, then the roots have imaginary parts and they are complex numbers.
Solved Example: 1-11-01
Roots of a quadratic equation are imaginary when discriminant is ______:
A. Zero
B. Greater than zero
C. Less than zero
D. Greater than or equal to zero
\[ax^2 + bx + c = 0\] Then $b^2-4ac$ is called the discriminant.
- If the discriminat is positive, the roots are real and distinct.
- If the discriminat is zero, the roots are real but equal.
- If the discriminat is negative, the roots are imaginary and complex conjugates of each other.
Correct Answer: C
Solved Example: 1-11-02
If $x^2−14x+k = 0$ is a perfect square, then k=?
A. -7
B. 196
C. -49
D. 49
Focus on the middle term coefficient.
If you take half of middle term coefficient, $\dfrac{14}{2} = 7$, then we can make the original expression $(x - 7)^2$ as still have the middle term as -14x.
In such case, the last term can be found of by expanding,
\[(x -7)^2 = x^2 - 14x + 49\]
Correct Answer: D
Solved Example: 1-11-03
If \[3x^2 - ax + 6 = ax^2 + 2x + 2\] has only one (repeated) solution, then the positive integral solution of a is:
A. 3
B. 2
C. 4
D. 5
Correct Answer: B
Solved Example: 1-11-04
One of the roots of the equation $x^2 - 12x + k = 0$ is x = 3. The other root is:
A. x = -4
B. x = 9
C. x = 4
D. x = -9
First substitute x = 3 in the given quadratic equation.
k = 27, Then use the quadratic formula.
Correct Answer: B